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x^2+x-15.75=0
a = 1; b = 1; c = -15.75;
Δ = b2-4ac
Δ = 12-4·1·(-15.75)
Δ = 64
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{64}=8$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(1)-8}{2*1}=\frac{-9}{2} =-4+1/2 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(1)+8}{2*1}=\frac{7}{2} =3+1/2 $
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